Simon,
> Could it be that we have overlooked this simple explanation and that the
> Haas and Stokes equation is actually quite good, but just not being
> applied?
That's probably part of it, but I've tried Haas and Stokes on a pure random
sample and it's still bad, or more specifically overly conservative.
--
--Josh
Josh Berkus
Aglio Database Solutions
San Francisco
