Re: gettimeofday() goes backwards on FreeBSD 4.9 - Mailing list pgsql-hackers

From Darcy Buskermolen
Subject Re: gettimeofday() goes backwards on FreeBSD 4.9
Date
Msg-id 200311281553.15808.darcy@wavefire.com
Whole thread Raw
In response to gettimeofday() goes backwards on FreeBSD 4.9  (Tom Lane <tgl@sss.pgh.pa.us>)
Responses Re: gettimeofday() goes backwards on FreeBSD 4.9  (Tom Lane <tgl@sss.pgh.pa.us>)
Re: gettimeofday() goes backwards on FreeBSD 4.9  ("Marc G. Fournier" <scrappy@postgresql.org>)
List pgsql-hackers
On November 28, 2003 12:33 pm, Tom Lane wrote:
> I said:
> > I'm wondering if there's an actual bug in gettimeofday() in this
> > platform, such that once in a while it returns a value that's off
> > a minute or so ...
>
> Whoa.  Try the following test program.  Then send it in to your friendly
> local BSD hackers ....
>
> > uname -a
>
> FreeBSD pgsql74.hub.org 4.9-PRERELEASE FreeBSD 4.9-PRERELEASE #3: Sat Sep
> 20 14:16:48 ADT 2003     root@neptune.hub.org:/usr/obj/usr/src/sys/kernel 
> i386
>
> > ./a.out
>
> out of order tv_sec: 1070050646 939970, prev 1070051342 516165
> out of order tv_sec: 1070051342 789127, prev 1070050646 939970
> out of order tv_usec: 1070051342 789127, prev 1070050646 939970
> out of order tv_sec: 1070050654 690255, prev 1070051350 216448
> out of order tv_sec: 1070051350 402412, prev 1070050654 690255
> out of order tv_usec: 1070051350 402412, prev 1070050654 690255
> out of order tv_sec: 1070050672 990359, prev 1070051368 416546
> out of order tv_sec: 1070051368 501648, prev 1070050672 990359
> out of order tv_usec: 1070051368 501648, prev 1070050672 990359
> out of order tv_sec: 1070050672 990363, prev 1070051368 516557
> out of order tv_sec: 1070051368 700227, prev 1070050672 990363
> out of order tv_usec: 1070051368 700227, prev 1070050672 990363
> out of order tv_sec: 1070050675 740524, prev 1070051371 216718
> out of order tv_sec: 1070051371 346521, prev 1070050675 740524
> out of order tv_usec: 1070051371 346521, prev 1070050675 740524
> out of order tv_sec: 1070050676 440415, prev 1070051371 916605
> out of order tv_usec: 1070050676 440415, prev 1070051371 916605
> out of order tv_sec: 1070051372 238348, prev 1070050676 440415
> out of order tv_usec: 1070051372 238348, prev 1070050676 440415
> ^C
>


I've been running this code on a pair of FreeBSD (i386) boxen, for some time 
now, one of which is a 4.8-STABLE, the other is a 5.2-BETA.

In 10 minutes of execution the 4.8 box has only shown the following:

out of order tv_sec: 1070063393 115226, prev 1070063391 381087
out of order tv_usec: 1070063393 115226, prev 1070063391 381087

the 5.2 box, hasn't outputed anything.  I'm goignt o run this test on some 
other boxen  I have and see what/ifany results are happening.

>
>             regards, tom lane
>
>
> #include <stdio.h>
> #include <sys/time.h>
>
> int
> main()
> {
>     struct timeval prevtime;
>     struct timeval curtime;
>
>     gettimeofday(&prevtime, NULL);
>
>     for (;;)
>     {
>         gettimeofday(&curtime, NULL);
>
>         if (curtime.tv_usec < 0 || curtime.tv_usec >= 1000000)
>             fprintf(stderr, "bogus tv_usec: %ld %ld, prev %ld %ld\n",
>                     (long int) curtime.tv_sec,
>                     (long int) curtime.tv_usec,
>                     (long int) prevtime.tv_sec,
>                     (long int) prevtime.tv_usec);
>
>         if (curtime.tv_sec < prevtime.tv_sec ||
>             curtime.tv_sec > prevtime.tv_sec + 1)
>             fprintf(stderr, "out of order tv_sec: %ld %ld, prev %ld %ld\n",
>                     (long int) curtime.tv_sec,
>                     (long int) curtime.tv_usec,
>                     (long int) prevtime.tv_sec,
>                     (long int) prevtime.tv_usec);
>
>         if (curtime.tv_usec < prevtime.tv_usec &&
>             curtime.tv_sec != prevtime.tv_sec + 1)
>             fprintf(stderr, "out of order tv_usec: %ld %ld, prev %ld %ld\n",
>                     (long int) curtime.tv_sec,
>                     (long int) curtime.tv_usec,
>                     (long int) prevtime.tv_sec,
>                     (long int) prevtime.tv_usec);
>
>         prevtime = curtime;
>     }
>
>     return 0;
> }
>
> ---------------------------(end of broadcast)---------------------------
> TIP 8: explain analyze is your friend

-- 
Darcy Buskermolen
Wavefire Technologies Corp.
ph: 250.717.0200
fx:  250.763.1759
http://www.wavefire.com



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