Once again ,
I have different logic based on match,
i need to know a prioi the number of matches.
See the actual code in response to Nigel .
Thanks for your response.
regds
mallah.
On Monday 10 Nov 2003 6:57 pm, Jaime Casanova wrote:
> Maybe you can use a for if there is only one row it will do the job just
> like if there were many rows:
>
> FOR referrer_keys IN SELECT * FROM cs_referrer_keys ORDER BY try_order
> LOOP
> a_output := a_output || '' IF v_'' || referrer_keys.kind || '' LIKE
> ''''''''''
>
> || referrer_keys.key_string || '''''''''' THEN RETURN
>
> ''''''
>
> || referrer_keys.referrer_type || ''''''; END IF;'';
>
> END LOOP;
>
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