> On Tue, Jan 04, 2000 at 06:47:39PM -0500, Bruce Momjian wrote:
> > Try:
> >
> > SELECT oid, *
> > FROM table
> > GROUP BY oid
> > HAVING count(*) > 1
> >
> > that should show your duplicates, and you can remove them using
> > table.oid = _bad_number_.
>
> ah, i thought each row had a unique oid, and thus, that query wouldn't show the
> duplicate content.
>
Oh, I thought they were using oid's for keys. I see now. Yes, you are
correct.
--
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