Re: position('' in '') returns 1 instead of 0 - Mailing list pgsql-bugs

From Tom Lane
Subject Re: position('' in '') returns 1 instead of 0
Date
Msg-id 15181.987629189@sss.pgh.pa.us
Whole thread Raw
In response to position('' in '') returns 1 instead of 0  (pgsql-bugs@postgresql.org)
List pgsql-bugs
Terry Carlin (terry@greatbridge.com) writes:
> While running an ODBC test suite against PostgreSQL 7.1, the test
> software reported that the ODBC command locate("", "") failed.
> It expected the result to be zero and it got a 1.

Evidently your ODBC test suite hasn't read the spec.  See 4.2.2.2 in
either SQL92 or SQL99:

         <position expression> determines the first position, if any, at
         which one string, S1, occurs within another, S2. If S1 is of length
         zero, then it occurs at position 1 for any value of S2. If S1 does
         not occur in S2, then zero is returned.

Whether this is useful or not is perhaps debatable, but it's indisputably
what the standard says to do.

            regards, tom lane

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