Andreas-3-2 wrote
> I never placed a bug-report. :}
> Could you give a hand?
Sure.
PostgreSQL homepage (postgresql.org)
"Report a Bug" link on right-hand side of page.
Fill in the form.
>>>SEND THIS>>>>
> drop table if exists sub_tab;
> drop table if exists main_tab;
> drop table if exists flag_1;
> drop table if exists flag_2;
>
> create temporary table flag_1 ( flag_1_id integer primary key, flag_1_t
> text );
> insert into flag_1 values (0, null ), ( 1, 'a' ), ( 2, 'b' ), ( 3, 'c' );
>
> create temporary table flag_2 ( flag_2_id integer primary key, flag_2_t
> text );
> insert into flag_2 values (0, null ), ( 1, 'a' ), ( 2, 'b' ), ( 3, 'c' );
>
> create temporary table main_tab ( main_id integer primary key, main_t
> text, flag_1_id integer references flag_1 ( flag_1_id ) );
> insert into main_tab values ( 1, 'Main 1', 1 ), ( 2, 'Main 2', 2 ), ( 3,
> 'Main 3', 3 );
>
> create temporary table sub_tab ( sub_id integer primary key, sub_t
> text, main_id integer references main_tab ( main_id ), flag_1_id integer
> references flag_1 ( flag_1_id ), flag_2_id integer references flag_2 (
> flag_2_id ) );
> insert into sub_tab values ( 1, 'Sub 1', 1, 3, 1 ), ( 2, 'Sub 2', 2, 2,
> 2 ), ( 3, 'Sub 3', 3, 1, 3 );
>
>
> select m.main_id, m.main_t, f.flag_1_t,
> x.sub_id, x.sub_t, x.flag_1_t, x.flag_2_t
> from main_tab as m
> join flag_1 as f using ( flag_1_id )
> left join
> (
> sub_tab as s
> join flag_2 as f2 using ( flag_2_id ) -- that
> way it works
> join flag_1 as f using ( flag_1_id )
> -- join flag_2 as f2 using ( flag_2_id ) -- that
> way it doesn't work
> ) as x using ( main_id );
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