variable in COPY TO variable - Mailing list pgsql-general
From Rob Shepherd
Subject variable in COPY TO variable
Date
Msg-id 1192548060.395271.35130@v23g2000prn.googlegroups.com
Whole thread Raw
Responses Re: variable in COPY TO variable
List pgsql-general
Dear postgres-users,

I'm currently working on a stored procedure, but having an error which
seems odd.

I'm following the synatx

COPY <tablename> TO 'filename'

.....but i'm trying to use a variable as the filename.

1 : CREATE OR REPLACE FUNCTION archive() RETURNS void AS
2 : $BODY$DECLARE
3 :     ts timestamp without time zone;
4 :     v_year integer;
5 :     v_month integer;
6 :     filename varchar(100);
7 : BEGIN
8 :     FOR i in 2..12 LOOP
9 :         ts = now() - (i || ' months')::interval;
10:         v_year = EXTRACT(YEAR FROM ts);
11:         v_month = EXTRACT(MONTH FROM ts);
12:
13:         IF (SELECT COUNT(1) FROM call_tickets WHERE EXTRACT(YEAR FROM
"Date/Hour") = v_year AND EXTRACT(MONTH FROM "Date/Hour") = v_month) >
0 THEN
14:             DROP TABLE IF EXISTS tt_archive;
15:             CREATE TEMP TABLE tt_archive AS (SELECT * FROM call_tickets
WHERE EXTRACT(YEAR FROM "Date/Hour") = v_year AND EXTRACT(MONTH FROM
"Date/Hour") = v_month);
16:             filename = '/usr/local/var/telephony_data/archive/
telephony_archive-' || v_year || v_month || '.psql';
17:             COPY tt_archive TO filename;
18:         END IF;
19:     END LOOP;
20: END; $BODY$
21: LANGUAGE 'plpgsql' VOLATILE;

returns the error....

ERROR: syntax error at or near "$1" at character 21
QUERY: COPY tt_archive TO $1
CONTEXT:  SQL statement in PL/PgSQL function "archive" near line 16


any pointer greatly appreciated.

R


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