On Mon, 2004-05-31 at 16:04, derrick wrote:
> Okay...
>
> I have tried this: AND caseId = ANY (ListOfNumbers)
> and get this error "parser: parse error at or near "$2" at character 1060"
> I have tried this: AND caseId = ANY (ListOfNumbers[])
> and get this error "parser: parse error at or near "$2" at character 1060"
> I have tried this: AND caseId = ANY (SELECT ListOfNumbers[])
> and get this error "parser: parse error at or near "]" at character 1071"
>
> The function only works when I assign an array element such as "ListOfNumbers
> [1]". In this case it works, however now I have lost the intent of the
> function using all the numbers in the array. This method only uses one.
>
> Is there a way to extract all of the elements from the array, no matter the
> size of the array?
It does work:
junk=# select * from ci order by f1;
f1
-----
5
34
45
67
69
123
(6 rows)
junk=# select * from ci where f1 = any ('{34,123,5}') order by
f1;
f1
-----
5
34
123
(3 rows)
In your original function definition, you declared the function as
taking (varchar, varchar). I think that should be (varchar,
varchar[]). If you haven't changed that, you are passing an array of
varchars into a parameter that expects a scalar varchar.
--
Oliver Elphick olly@lfix.co.uk
Isle of Wight http://www.lfix.co.uk/oliver
GPG: 1024D/A54310EA 92C8 39E7 280E 3631 3F0E 1EC0 5664 7A2F A543 10EA
========================================
"How precious also are thy thoughts unto me, O God! how
great is the sum of them! If I should count them, they
are more in number than the sand; when I awake, I am
still with thee." Psalms 139: 17,18
