--- On Wed, 1/2/08, Tom Lane <tgl@sss.pgh.pa.us> wrote:
> [ pokes at it... ] The reason is that you defined both the trigger and
> the testing function as STABLE, which means that they see a snapshot of
> the database as of the start of the calling SQL command. In the first
> case that's the UPDATE, in the second it's the COMMIT.
Thanks for the help Tom. This information is good to know.
Regards,
Richard Broersma Jr.