Am Mo, 2003-09-01 um 03.44 schrieb Luis H.:
> I have two tables, table A contains users (id, username, password) , and
> table B contains a row that signifies the 'owner' of each particular entry,
> referencing an id in A.
>
> so example
>
> table A
> id username password
> ------------------------
> 1 me *****
> 2 you *******
>
> table B
> description owner
> -------------------------
> 'something cool' 2
> 'another thing' 1
>
>
> What I want to do is do a query where I order table B by owner, but
> alphabetically by username. The problem, obviously, is that table B only
> contains id's (numbers, indexing to A), which don't correspond to the
> alphabetical order of the usernames.
SELECT * FROM a JOIN b ON (a.id=b.owner) ORDER BY a.username
or
SELECT * FROM a, b WHERE a.id=b.owner ORDER BY a.username
If you had the columnnames the same in A and B for the id you could do:
SELECT * FROM a JOIN B USING (id_a) ORDER BY a.username
> I'm not very familiar with subqueries, but I expect I should be able to
> somehow select ID's from table A ordered by username, and use this index to
> order table B by owner.
No need for subselects here
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