Re: Anyone understand shared-memory space usage? - Mailing list pgsql-hackers
From | Tom Lane |
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Subject | Re: Anyone understand shared-memory space usage? |
Date | |
Msg-id | 10605.919730969@sss.pgh.pa.us Whole thread Raw |
In response to | Re: Anyone understand shared-memory space usage? (Tom Lane <tgl@sss.pgh.pa.us>) |
Responses |
Re: [HACKERS] Re: Anyone understand shared-memory space usage?
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List | pgsql-hackers |
I wrote: > I would like someone to check my work; if the code was really as > broken as I think it was, we should have been seeing more problems > than we were. I spent an hour tracing through startup of 6.4.x, and I now understand why the thing doesn't crash despite the horrible bugs in ShmemInitHash. Read on, if you have a strong stomach. First off, ShmemInitHash allocates too small a chunk of space for the hash header + directory (because it computes the size of the directory as log2(max_size) *bytes* not longwords). Then, it computes the wrong address for the directory --- the expressioninfoP->dir = (long *) (location + sizeof(HHDR)); looks good until you remember that location is a pointer to long not a pointer to char. Upshot: the address computed for "dir" is typically 168 bytes past the end of the space actually allocated for it. Why is this not fatal? Well, the very next ShmemAlloc call is always to create the first "segment" of the hashtable; this is always for 1024 bytes, so the dir pointer is no longer pointing to nowhere. It is in fact pointing at the 42'nd entry of its own first segment. (HHGTTG fans can find deep significance in this.) In other words entry 42 of the hash segment points back at the segment itself. When you work through the logic in dynahash.c, you discover that the upshot of this is that (a) the segment appears to be the first item on its own 42'nd hash-bucket chain, and (b) the 0'th and 42'nd hash-bucket chains are therefore the same list, or more accurately the 0'th chain is the cdr of the 42'nd chain since it doesn't appear to contain the segment itself. As long as no searched-for hash key with a hash value of 0 or 42 happens to match whatever the first few words of the segment are, things pretty much work. The only way you'd really notice is that hash_seq() will report some of the hashtable records twice, and will also report one completely bogus "record" that is the hash segment. Our uses of hash_seq() are apparently robust enough not to be bothered. Things don't go to hell in a handbasket until and unless the hashtable is expanded past 256 entries. At that point another segment is allocated and its pointer is stored in slot 43 of the old segment, causing all the table entries that were in hashbucket 43 to instantly disappear from view --- they can't be found by searching the table anymore. Also, hashchain 43 now appears to be the same as hashchain 256 (the first of the new segment), but that's not going to bother anyone any worse than the first duplicated chain did. I think it's entirely likely that this set of bugs can account for flaky behavior seen in installations with more than 256 shared-memory buffers (postmaster -B > 256), more than 256 simultaneously held locks (have no idea how to translate that into user terms), or more than 256 concurrent backends. I'm still wondering whether that might describe Daryl Dunbar's problem with locks not getting released, for example. regards, tom lane
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