Gavin Sherry <swm@alcove.com.au> writes:
> We want to answer the following: for each employee: what is their rank in
> terms of salary and what is their rank in terms of age. This query
> answers that:
> select empno, rank() over (order by salary) as srank,
> rank() over (order by age) as arank
> from employees order by empno;
Eeek. This seems like the worst sort of action-at-a-distance. How does
rank() know what value it's supposed to report the rank of?
regards, tom lane
