> CREATE FUNCTION update_pass() RETURNS integer AS $$
> UPDATE hoy SET pass_md5=md5(pass) WHERE id=new.id;
> SELECT 1;
> $$ LANGUAGE SQL;
>
> CREATE TRIGGER triger_users_pass_md5
> AFTER INSERT OR UPDATE
> ON hoy FOR EACH ROW
> EXECUTE PROCEDURE update_pass;
I understand the ideea, but don't know how to apply it.
I also receive the error that NEW must be definde as a rule.
Still... not working...
----- Original Message -----
From: "daq" <daq@ugyvitelszolgaltato.hu>
To: "Andrei Bintintan" <klodoma@ar-sd.net>
Cc: <Pgsql-sql@postgresql.org>
Sent: Monday, July 18, 2005 4:32 PM
Subject: Re: [SQL] Create trigger for auto update function
> Hello Andrei,
>
> Monday, July 18, 2005, 2:24:41 PM, you wrote:
>
> AB> Hi to all,
>
> AB> I have a table:
> AB> create table hoy(
> AB> id serial,
> AB> pass varchar(40),
> AB> pass_md5 varchar(40);
>
> AB> Now, I want to write a trigger function that automatically updates the
> pass_md5 with the md5 function of the pass.
>
> AB> I tried this:
>
> AB> CREATE FUNCTION update_pass(integer) RETURNS integer AS $$
> AB> UPDATE hoy SET pass_md5=md5(pass) WHERE id=$1;
> AB> SELECT 1;
> AB> $$ LANGUAGE SQL;
>
> AB> and
>
> AB> CREATE TRIGGER triger_users_pass_md5
> AB> AFTER INSERT OR UPDATE
> AB> ON hoy
> AB> EXECUTE PROCEDURE update_pass(integer);
>
> What will be the param of the trigger procedure?
>
> Try this way:
>
> CREATE FUNCTION update_pass() RETURNS integer AS $$
> UPDATE hoy SET pass_md5=md5(pass) WHERE id=new.id;
> SELECT 1;
> $$ LANGUAGE SQL;
>
> CREATE TRIGGER triger_users_pass_md5
> AFTER INSERT OR UPDATE
> ON hoy FOR EACH ROW
> EXECUTE PROCEDURE update_pass;
>
>
> DAQ
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 9: In versions below 8.0, the planner will ignore your desire to
> choose an index scan if your joining column's datatypes do not
> match
>
>
