Re: - Mailing list pgsql-sql

From Louise Cofield
Subject Re:
Date
Msg-id 00e401c3a7ae$74146e70$7801a8c0@Louise
Whole thread Raw
In response to ...  (ronald@my.msuiit.edu.ph)
List pgsql-sql
You will have to use a WHERE clause or a JOIN in query three, so you
will have to include some field, such as itemno, in the result sets of
both query1 and query2 on which you can join with where or join.  Such
as:

Select query1.sumofqty as sum1, query2.sumofqty as sum2, query1.sumofqty
- query2.sumofqty as remain from query1, query2 where query1.<itemno> =
query2.<itemno>



-----Original Message-----
From: pgsql-sql-owner@postgresql.org
[mailto:pgsql-sql-owner@postgresql.org] On Behalf Of
ronald@my.msuiit.edu.ph
Sent: Friday, November 07, 2003 11:52 PM
To: pgsql-sql@postgresql.org
Subject: [SQL]



Hello everyone, Good day! Could anyone help me translate this query in
Microsoft Access to Postgresql. I'm having a difficulty. Pls...

Query1:
SELECT items.description, Sum(supplieditems.qty) AS SumOfqty FROM items
INNER JOIN supplieditems ON items.itemno = supplieditems.itemno GROUP BY
items.description;

Query2:
SELECT [items].[description], Sum([customer].[qty]) AS SumOfqty FROM
(items INNER JOIN OtherItem ON [items].[itemno]=[OtherItem].[Itemno])
INNER JOIN customer ON [OtherItem].[Itemno]=[customer].[itemcode]
GROUP BY [items].[description];

Query3:
SELECT [Query1].[SumOfqty], [Query2].[SumOfqty],
[Query1]![SumOfqty]-[Query2]![SumOfqty] AS remain FROM Query1, Query2;

I have translated Query1 and Query2 in POSTGRESQL but I don't know how
to implement Query3.


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