Select id from T where name = 'bleh'
UNION ALL
Select id from T where description = 'bleh';
Will get you the resultset you want, but: I don't believe that you can do a
GROUP BY on it.
If you just want counts, as you describe below, you could do something like:
SELECT 'Only One', (SELECT count (id) from T where name = 'bleh' OR
description = 'bleh') - (SELECT count (id) from T where name = 'bleh' AND
description = 'bleh')
UNION
SELECT 'Both', (SELECT count (id) from T where name = 'bleh' AND description
= 'bleh');
----- Original Message -----
From: "Mark Mikulec" <mm98au@badger.ac.brocku.ca>
To: <pgsql-sql@postgresql.org>
Sent: Tuesday, August 14, 2001 7:40 PM
Subject: Sequential select queries...??
> Hello,
>
> At first I thought what I was trying to do was simple and could be done
> easily - but alas, I've spent way too much time and could not figure out
> how to get the results in question.
>
> Let's say I have a table T comprised of id of type integer, name and
> description both of type text.
>
> What i'd like to do is the following:
>
> Select id from T where name = 'bleh';
>
> and
>
> Select id from T where description = 'bleh';
>
> and result both results in the same result set. That is, duplicate id's
> if they appear. So then I could do a GROUP BY and a COUNT to see how
> many appeared in only one, and how many appeared in both.
>
> Could someone help me? I've tried countless different sql queries, can't
> seem to get one to work. If I can just get those duplicate id's in the
> query.. then I'd be laughing and then I can complete my task.
>
> Thanks in advance,
>
> Mark
>
>
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>
>
