Re: Need some advice on a difficult query - Mailing list pgsql-general

Hi Mike,

here is an untested "weird nested query" for your problem:

SELECT * FROM Recipes r where lower(RecipeTitle) like lower('%pasta%')

and not exists

(select 1 from ingredients inner join blacklist using (IngredientId) where RecipeId = r.RecipeId and blacklist.UserId = 123 limit 1);

Should be quite fast with the right indexes.

Timo

Hi all - I'd like some advice on how to write a rather complicated (for me, anyway) query and if there's any nifty Postgres features I can take advantage of in this situation.  Imagine a database, if you will, used to store recipes.  I have a recipes table:

RecipeId
RecipeTitle
RecipeRating

And an ingredients table:

RecipeId
IngredientId
Amount

When the user searches for a new pasta dish, the UI would generate a query something like this:

SELECT * FROM Recipes where RecipeTitle ilike '%pasta%';

I only need the data from the recipes table since I display a summary of the search results and don't load the full recipe until the user clicks on the link.  This works great.  However, I'm now in the process of implementing an ingredient blacklist.  This means NEVER show me any recipes which have one of my blacklisted ingredients, as if I ingest any I will die a painful death.  Or maybe my god will smite me or something.  This table would look like:

UserId
IngredientId

Ok, now the question.  What's the best way to query for my pasta dish above while excluding any recipe that contains one or more of my blacklisted ingredients?  I don't want to join in Ingredients because I'd then have a row for each ingredient of each recipe (which would cause me massive headache and redesign)..   I thought about some weird nested query, but I'm concerned it might be slow (searching for recipes is the central feature of my site and must be fast, fast and fast).  This basically boils down to some weird Cartesian product thing.

I am, however, willing to redesign the mechanism I store blacklisted ingredients with.  I could store this as an array on the Users table, or anything else that might make things easier.  Any advice on this?

Mike